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Molecular formula

C98H88Cl5NP4Ru2

3 compounds have this formula on CompoundList.

Molar mass
1783.07g/mol
Monoisotopic mass
1781.2397Da
Atoms
198
Elements
6

The formula C98H88Cl5NP4Ru2 describes a molecule made of 98 carbon atoms, 88 hydrogen atoms, 5 chlorine atoms, 1 nitrogen atom, 4 phosphorus atoms and 2 ruthenium atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 9866.01%
    12.011 × 98 = 1177.078 g/mol
  • H Hydrogen × 884.97%
    1.008 × 88 = 88.704 g/mol
  • Cl Chlorine × 59.94%
    35.45 × 5 = 177.250 g/mol
  • N Nitrogen × 10.79%
    14.007 × 1 = 14.007 g/mol
  • P Phosphorus × 46.95%
    30.974 × 4 = 123.896 g/mol
  • Ru Ruthenium × 211.34%
    101.07 × 2 = 202.140 g/mol
Look up another formula

Compounds with the formula C98H88Cl5NP4Ru2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Dimethylammonium dichlorotri(MU-chloro)bis[(R)-(+)-2,2'-bis(DI-P-tolylphosphino)-1,1'-binaphthyl]diruthenate(II) chemical structure, C98H88Cl5NP4Ru2
Dimethylammonium dichlorotri(MU-chloro)bis[(R)-(+)-2,2'-bis(DI-P-tolylphosphino)-1,1'-binaphthyl]diruthenate(II)
C98H88Cl5NP4Ru2
[1-[2-Bis(4-methylphenyl)phosphanylnaphthalen-1-yl]naphthalen-2-yl]-bis(4-methylphenyl)phosphane, dichlororuthenium, N-methylmethanamine, hydrochloride chemical structure, C98H88Cl5NP4Ru2
[1-[2-Bis(4-methylphenyl)phosphanylnaphthalen-1-yl]naphthalen-2-yl]-bis(4-methylphenyl)phosphane, dichlororuthenium, N-methylmethanamine, hydrochloride
C98H88Cl5NP4Ru2
[1-[2-(Bis-p-tolylphosphanyl)-1-naphthyl]-2-naphthyl]-bis(P-tolyl)phosphane, dichlororuthenium, dimethylammonium, chloride chemical structure, C98H88Cl5NP4Ru2
[1-[2-(Bis-p-tolylphosphanyl)-1-naphthyl]-2-naphthyl]-bis(P-tolyl)phosphane, dichlororuthenium, dimethylammonium, chloride
C98H88Cl5NP4Ru2

Frequently asked questions

What is the molar mass of C98H88Cl5NP4Ru2?

The molar mass of C98H88Cl5NP4Ru2 is 1783.07 g/mol, calculated from standard atomic weights for 98 carbon atoms, 88 hydrogen atoms, 5 chlorine atoms, 1 nitrogen atom, 4 phosphorus atoms and 2 ruthenium atoms. The monoisotopic mass is 1781.2397 Da.

How many compounds have the formula C98H88Cl5NP4Ru2?

CompoundList lists 3 compounds with the molecular formula C98H88Cl5NP4Ru2, including Dimethylammonium dichlorotri(MU-chloro)bis[(R)-(+)-2,2'-bis(DI-P-tolylphosphino)-1,1'-binaphthyl]diruthenate(II), [1-[2-Bis(4-methylphenyl)phosphanylnaphthalen-1-yl]naphthalen-2-yl]-bis(4-methylphenyl)phosphane, dichlororuthenium, N-methylmethanamine, hydrochloride, [1-[2-(Bis-p-tolylphosphanyl)-1-naphthyl]-2-naphthyl]-bis(P-tolyl)phosphane, dichlororuthenium, dimethylammonium, chloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.