C9H14BF4N
2 compounds have this formula on CompoundList.
- Molar mass
- 223.02g/mol
- Monoisotopic mass
- 223.1155Da
- Atoms
- 29
- Elements
- 5
The formula C9H14BF4N describes a molecule made of 9 carbon atoms, 14 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 948.47%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 146.33%1.008 × 14 = 14.112 g/mol
- B Boron × 14.85%10.81 × 1 = 10.810 g/mol
- F Fluorine × 434.07%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 16.28%14.007 × 1 = 14.007 g/mol
Compounds with the formula C9H14BF4N
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C9H14BF4N?
The molar mass of C9H14BF4N is 223.02 g/mol, calculated from standard atomic weights for 9 carbon atoms, 14 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. The monoisotopic mass is 223.1155 Da.
How many compounds have the formula C9H14BF4N?
CompoundList lists 2 compounds with the molecular formula C9H14BF4N, including 1-Butylpyridinium tetrafluoroborate, Phenyltrimethylammonium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.