CompoundList
Molecular formula

C9H14BNO4

12 compounds have this formula on CompoundList.

Molar mass
211.02g/mol
Monoisotopic mass
211.1016Da
Atoms
29
Elements
5

The formula C9H14BNO4 describes a molecule made of 9 carbon atoms, 14 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 951.23%
    12.011 × 9 = 108.099 g/mol
  • H Hydrogen × 146.69%
    1.008 × 14 = 14.112 g/mol
  • B Boron × 15.12%
    10.81 × 1 = 10.810 g/mol
  • N Nitrogen × 16.64%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 430.33%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C9H14BNO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C9H14BNO4?

The molar mass of C9H14BNO4 is 211.02 g/mol, calculated from standard atomic weights for 9 carbon atoms, 14 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 211.1016 Da.

How many compounds have the formula C9H14BNO4?

CompoundList lists 12 compounds with the molecular formula C9H14BNO4, including 1-(tert-Butoxycarbonyl)-2-pyrroleboronic Acid, 1-(tert-Butoxycarbonyl)pyrrole-3-boronic acid, (2,6-Diethoxypyridin-3-yl)boronic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.