CompoundList
Molecular formula

C9H15I

19 compounds have this formula on CompoundList.

Molar mass
250.12g/mol
Monoisotopic mass
250.0218Da
Atoms
25
Elements
3
Rings plus double bonds
2

The formula C9H15I describes a molecule made of 9 carbon atoms, 15 hydrogen atoms and 1 iodine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 943.22%
    12.011 × 9 = 108.099 g/mol
  • H Hydrogen × 156.05%
    1.008 × 15 = 15.120 g/mol
  • I Iodine × 150.74%
    126.9 × 1 = 126.900 g/mol
Look up another formula

Compounds with the formula C9H15I

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 19 of 19 compounds

Frequently asked questions

What is the molar mass of C9H15I?

The molar mass of C9H15I is 250.12 g/mol, calculated from standard atomic weights for 9 carbon atoms, 15 hydrogen atoms and 1 iodine atom. The monoisotopic mass is 250.0218 Da.

How many compounds have the formula C9H15I?

CompoundList lists 19 compounds with the molecular formula C9H15I, including 1-tert-Butyl-3-iodobicyclo(1.1.1)pentane, 1-(5-Hexenyl)-2-iodocyclopropane, 9-Iodonon-1-yne. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C9H15I?

C9H15I has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.