C9H9BrO2Zn
4 compounds have this formula on CompoundList.
- Molar mass
- 294.45g/mol
- Monoisotopic mass
- 291.9077Da
- Atoms
- 22
- Elements
- 5
The formula C9H9BrO2Zn describes a molecule made of 9 carbon atoms, 9 hydrogen atoms, 1 bromine atom, 2 oxygen atoms and 1 zinc atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 936.71%12.011 × 9 = 108.099 g/mol
- H Hydrogen × 93.08%1.008 × 9 = 9.072 g/mol
- Br Bromine × 127.14%79.904 × 1 = 79.904 g/mol
- O Oxygen × 210.87%15.999 × 2 = 31.998 g/mol
- Zn Zinc × 122.20%65.38 × 1 = 65.380 g/mol
Compounds with the formula C9H9BrO2Zn
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
![Bromo[2-(ethoxycarbonyl-kappaO)phenyl-kappaC]zinc chemical structure, C9H9BrO2Zn, CAS 131379-40-3](/s/LRSRESIMIGVTLH-UHFFFAOYSA-M.svg)
![Zinc, bromo[3-(ethoxycarbonyl)phenyl]- chemical structure, C9H9BrO2Zn, CAS 131379-38-9](/s/ZKKAIKLQEZUTMG-UHFFFAOYSA-M.svg)
Frequently asked questions
What is the molar mass of C9H9BrO2Zn?
The molar mass of C9H9BrO2Zn is 294.45 g/mol, calculated from standard atomic weights for 9 carbon atoms, 9 hydrogen atoms, 1 bromine atom, 2 oxygen atoms and 1 zinc atom. The monoisotopic mass is 291.9077 Da.
How many compounds have the formula C9H9BrO2Zn?
CompoundList lists 4 compounds with the molecular formula C9H9BrO2Zn, including Zinc bromide 4-(ethoxycarbonyl)benzen-1-ide (1/1/1), Bromo[2-(ethoxycarbonyl-kappaO)phenyl-kappaC]zinc, Zinc, bromo[3-(ethoxycarbonyl)phenyl]-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.