CH12N4O3Zn
1 compound has this formula on CompoundList.
- Molar mass
- 193.51g/mol
- Monoisotopic mass
- 192.0201Da
- Atoms
- 21
- Elements
- 5
The formula CH12N4O3Zn describes a molecule made of 1 carbon atom, 12 hydrogen atoms, 4 nitrogen atoms, 3 oxygen atoms and 1 zinc atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 16.21%12.011 × 1 = 12.011 g/mol
- H Hydrogen × 126.25%1.008 × 12 = 12.096 g/mol
- N Nitrogen × 428.95%14.007 × 4 = 56.028 g/mol
- O Oxygen × 324.80%15.999 × 3 = 47.997 g/mol
- Zn Zinc × 133.79%65.38 × 1 = 65.380 g/mol
Compounds with the formula CH12N4O3Zn
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of CH12N4O3Zn?
The molar mass of CH12N4O3Zn is 193.51 g/mol, calculated from standard atomic weights for 1 carbon atom, 12 hydrogen atoms, 4 nitrogen atoms, 3 oxygen atoms and 1 zinc atom. The monoisotopic mass is 192.0201 Da.
How many compounds have the formula CH12N4O3Zn?
CompoundList lists 1 compound with the molecular formula CH12N4O3Zn, including Zinc(2+), tetraammine-, (T-4)-, carbonate (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.