Ce3H2IN9O33
We do not list any compound with this exact formula yet.
- Molar mass
- 1203.31g/mol
- Atoms
- 48
- Elements
- 5
The formula Ce3H2IN9O33 describes a molecule made of 3 cerium atoms, 2 hydrogen atoms, 1 iodine atom, 9 nitrogen atoms and 33 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Ce Cerium × 334.93%140.12 × 3 = 420.360 g/mol
- H Hydrogen × 20.17%1.008 × 2 = 2.016 g/mol
- I Iodine × 110.55%126.9 × 1 = 126.900 g/mol
- N Nitrogen × 910.48%14.007 × 9 = 126.063 g/mol
- O Oxygen × 3343.88%15.999 × 33 = 527.967 g/mol
Compounds with the formula Ce3H2IN9O33
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of Ce3H2IN9O33?
The molar mass of Ce3H2IN9O33 is 1203.31 g/mol, calculated from standard atomic weights for 3 cerium atoms, 2 hydrogen atoms, 1 iodine atom, 9 nitrogen atoms and 33 oxygen atoms.