Cl6H42N14O2Ru3
We do not list any compound with this exact formula yet.
- Molar mass
- 786.34g/mol
- Atoms
- 67
- Elements
- 5
The formula Cl6H42N14O2Ru3 describes a molecule made of 6 chlorine atoms, 42 hydrogen atoms, 14 nitrogen atoms, 2 oxygen atoms and 3 ruthenium atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Cl Chlorine × 627.05%35.45 × 6 = 212.700 g/mol
- H Hydrogen × 425.38%1.008 × 42 = 42.336 g/mol
- N Nitrogen × 1424.94%14.007 × 14 = 196.098 g/mol
- O Oxygen × 24.07%15.999 × 2 = 31.998 g/mol
- Ru Ruthenium × 338.56%101.07 × 3 = 303.210 g/mol
Compounds with the formula Cl6H42N14O2Ru3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of Cl6H42N14O2Ru3?
The molar mass of Cl6H42N14O2Ru3 is 786.34 g/mol, calculated from standard atomic weights for 6 chlorine atoms, 42 hydrogen atoms, 14 nitrogen atoms, 2 oxygen atoms and 3 ruthenium atoms.