BiH10N3O14
We do not list any compound with this exact formula yet.
- Molar mass
- 485.07g/mol
- Atoms
- 28
- Elements
- 4
The formula BiH10N3O14 describes a molecule made of 1 bismuth atom, 10 hydrogen atoms, 3 nitrogen atoms and 14 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Bi Bismuth × 143.08%208.98 × 1 = 208.980 g/mol
- H Hydrogen × 102.08%1.008 × 10 = 10.080 g/mol
- N Nitrogen × 38.66%14.007 × 3 = 42.021 g/mol
- O Oxygen × 1446.18%15.999 × 14 = 223.986 g/mol
Compounds with the formula BiH10N3O14
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of BiH10N3O14?
The molar mass of BiH10N3O14 is 485.07 g/mol, calculated from standard atomic weights for 1 bismuth atom, 10 hydrogen atoms, 3 nitrogen atoms and 14 oxygen atoms.