Cl3H14O7Pr
We do not list any compound with this exact formula yet.
- Molar mass
- 373.37g/mol
- Atoms
- 25
- Elements
- 4
The formula Cl3H14O7Pr describes a molecule made of 3 chlorine atoms, 14 hydrogen atoms, 7 oxygen atoms and 1 praseodymium atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Cl Chlorine × 328.48%35.45 × 3 = 106.350 g/mol
- H Hydrogen × 143.78%1.008 × 14 = 14.112 g/mol
- O Oxygen × 730.00%15.999 × 7 = 111.993 g/mol
- Pr Praseodymium × 137.74%140.91 × 1 = 140.910 g/mol
Compounds with the formula Cl3H14O7Pr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of Cl3H14O7Pr?
The molar mass of Cl3H14O7Pr is 373.37 g/mol, calculated from standard atomic weights for 3 chlorine atoms, 14 hydrogen atoms, 7 oxygen atoms and 1 praseodymium atom.