Cl10H18N4ORu2
We do not list any compound with this exact formula yet.
- Molar mass
- 646.81g/mol
- Atoms
- 35
- Elements
- 5
The formula Cl10H18N4ORu2 describes a molecule made of 10 chlorine atoms, 18 hydrogen atoms, 4 nitrogen atoms, 1 oxygen atom and 2 ruthenium atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Cl Chlorine × 1054.81%35.45 × 10 = 354.500 g/mol
- H Hydrogen × 182.81%1.008 × 18 = 18.144 g/mol
- N Nitrogen × 48.66%14.007 × 4 = 56.028 g/mol
- O Oxygen × 12.47%15.999 × 1 = 15.999 g/mol
- Ru Ruthenium × 231.25%101.07 × 2 = 202.140 g/mol
Compounds with the formula Cl10H18N4ORu2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of Cl10H18N4ORu2?
The molar mass of Cl10H18N4ORu2 is 646.81 g/mol, calculated from standard atomic weights for 10 chlorine atoms, 18 hydrogen atoms, 4 nitrogen atoms, 1 oxygen atom and 2 ruthenium atoms.