Br3H2OPr
We do not list any compound with this exact formula yet.
- Molar mass
- 398.64g/mol
- Atoms
- 7
- Elements
- 4
The formula Br3H2OPr describes a molecule made of 3 bromine atoms, 2 hydrogen atoms, 1 oxygen atom and 1 praseodymium atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Br Bromine × 360.13%79.904 × 3 = 239.712 g/mol
- H Hydrogen × 20.51%1.008 × 2 = 2.016 g/mol
- O Oxygen × 14.01%15.999 × 1 = 15.999 g/mol
- Pr Praseodymium × 135.35%140.91 × 1 = 140.910 g/mol
Compounds with the formula Br3H2OPr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of Br3H2OPr?
The molar mass of Br3H2OPr is 398.64 g/mol, calculated from standard atomic weights for 3 bromine atoms, 2 hydrogen atoms, 1 oxygen atom and 1 praseodymium atom.