AuBr4H3O
We do not list any compound with this exact formula yet.
- Molar mass
- 535.61g/mol
- Atoms
- 9
- Elements
- 4
The formula AuBr4H3O describes a molecule made of 1 gold atom, 4 bromine atoms, 3 hydrogen atoms and 1 oxygen atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Au Gold × 136.77%196.97 × 1 = 196.970 g/mol
- Br Bromine × 459.67%79.904 × 4 = 319.616 g/mol
- H Hydrogen × 30.56%1.008 × 3 = 3.024 g/mol
- O Oxygen × 12.99%15.999 × 1 = 15.999 g/mol
Compounds with the formula AuBr4H3O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of AuBr4H3O?
The molar mass of AuBr4H3O is 535.61 g/mol, calculated from standard atomic weights for 1 gold atom, 4 bromine atoms, 3 hydrogen atoms and 1 oxygen atom.