C11H14ClN5
45 compounds have this formula on CompoundList.
- Molar mass
- 251.72g/mol
- Monoisotopic mass
- 257.1314Da
- Atoms
- 31
- Elements
- 4
- Rings plus double bonds
- 7
The formula C11H14ClN5 describes a molecule made of 11 carbon atoms, 14 hydrogen atoms, 1 chlorine atom and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1152.49%12.011 × 11 = 132.121 g/mol
- H Hydrogen × 145.61%1.008 × 14 = 14.112 g/mol
- Cl Chlorine × 114.08%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 527.82%14.007 × 5 = 70.035 g/mol
Compounds with the formula C11H14ClN5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 45 of 45 compounds
- 3-(Azetidin-3-yl(1H-1,2,3-triazol-1-yl)methyl)pyridine hydrochloride1824018-46-3C11H14ClN5
- 3-tert-Butyl-1-(6-chloropyrazin-2-yl)pyrazol-5-amine642459-11-8C11H14ClN5
- N''-(4,7-Dimethylquinazolin-2-yl)guanidine--hydrogen chloride (1/1)5361-21-7C11H14ClN5
- 1-(6-Chloro-3-pyridazinyl)-N-(1-methylethyl)-1H-pyrazole-4-methanamine1208087-75-5C11H14ClN5
- Imidazo[1,5-a]pyrazine,8-chloro-3-(4-methyl-1-piperazinyl)-1326281-78-0C11H14ClN5
- 3-(Azetidin-3-yl(2H-1,2,3-triazol-2-yl)methyl)pyridine hydrochloride1823861-94-4C11H14ClN5
- 8-(1,2,3,6-Tetrahydropyridin-4-yl)-[1,2,4]triazolo[1,5-a]pyridin-2-amine hydrochloride1673527-30-4C11H14ClN5
- N-{[4-(1H-pyrazol-3-yl)phenyl]methyl}guanidine hydrochloride1955522-61-8C11H14ClN5
- 2-Guanidinylpropyl-5(6)-chloro-benzimidazol1060803-57-7C11H14ClN5
- 6-Chloro-2-ethyl-N-[(1-methylpyrazol-4-yl)methyl]pyrimidin-4-amine1424376-35-1C11H14ClN5
- 1-(Pyrimidin-2-yl)-4,5,6,7-tetrahydro-1H-indazol-4-amine hydrochloride1955515-43-1C11H14ClN5
- 5-(3,5-Dimethyl-1H-pyrazol-1-yl)pyridine-2-carboximidamide hydrochloride1955556-87-2C11H14ClN5
- 2-Chloro-N-isopropyl-5-(1-methyl-1H-1,2,3-triazol-4-yl)pyridin-4-amine2058036-56-7C11H14ClN5
- 3-(6-Methylpyridin-2-yl)-5,6,7,8-tetrahydro-[1,2,4]triazolo[4,3-a]pyrazine hydrochloride2990109-79-8C11H14ClN5
- 3-Chloro-5-cyclopropyl-4-(1-propan-2-ylpyrazol-4-yl)-1,2,4-triazole1284674-84-5C11H14ClN5
- 2-Chloro-4-(4-methylpiperazin-1-yl)-5H-pyrrolo[3,2-d]pyrimidine1841081-41-1C11H14ClN5
- 6-Chloro-1-(1-methylpiperidin-4-yl)-1H-pyrazolo[3,4-d]pyrimidine1443288-00-3C11H14ClN5
- 6-Chloro-1-(1-methylpiperidin-3-yl)-1H-pyrazolo[3,4-d]pyrimidine1443292-26-9C11H14ClN5
- 5-(4-Amino-1-methyl-1H-pyrazol-5-yl)-3-chloro-N,N-dimethylpyridin-2-amine2137957-88-9C11H14ClN5
- 7-Chloro-3-cycloheptyl-3H-[1,2,3]triazolo[4,5-d]pyrimidine65019-04-7C11H14ClN5
- 5-Chloro-3-cycloheptyl-3H-[1,2,3]triazolo[4,5-d]pyrimidine2206321-83-5C11H14ClN5
Frequently asked questions
What is the molar mass of C11H14ClN5?
The molar mass of C11H14ClN5 is 251.72 g/mol, calculated from standard atomic weights for 11 carbon atoms, 14 hydrogen atoms, 1 chlorine atom and 5 nitrogen atoms. The monoisotopic mass is 257.1314 Da.
How many compounds have the formula C11H14ClN5?
CompoundList lists 45 compounds with the molecular formula C11H14ClN5, including Cycloguanil, N-(4,5-Dihydro-1H-imidazol-2-yl)-2-methyl-2H-indazol-4-amine monohydrochloride, 1,3,5-Triazine-2,4-diamine, 1-(3-chlorophenyl)-1,6-dihydro-6,6-dimethyl-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C11H14ClN5?
C11H14ClN5 has a degree of unsaturation of 7. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.