CompoundList
Molecular formula

C12H14ClNO3

301 compounds have this formula on CompoundList.

Molar mass
255.70g/mol
Monoisotopic mass
255.0662Da
Atoms
31
Elements
5
Rings plus double bonds
6

The formula C12H14ClNO3 describes a molecule made of 12 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1256.37%
    12.011 × 12 = 144.132 g/mol
  • H Hydrogen × 145.52%
    1.008 × 14 = 14.112 g/mol
  • Cl Chlorine × 113.86%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 15.48%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 318.77%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C12H14ClNO3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 301 to 301 of 301 compounds

Frequently asked questions

What is the molar mass of C12H14ClNO3?

The molar mass of C12H14ClNO3 is 255.70 g/mol, calculated from standard atomic weights for 12 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 255.0662 Da.

How many compounds have the formula C12H14ClNO3?

CompoundList lists 301 compounds with the molecular formula C12H14ClNO3, including Ethyl N-[(2S)-1-chloro-1-oxo-3-phenylpropan-2-yl]carbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C12H14ClNO3?

C12H14ClNO3 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.