CompoundList
Molecular formula

C15H14N2O3

549 compounds have this formula on CompoundList.

Molar mass
270.29g/mol
Monoisotopic mass
270.1004Da
Atoms
34
Elements
4
Rings plus double bonds
10

The formula C15H14N2O3 describes a molecule made of 15 carbon atoms, 14 hydrogen atoms, 2 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1566.66%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 145.22%
    1.008 × 14 = 14.112 g/mol
  • N Nitrogen × 210.36%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 317.76%
    15.999 × 3 = 47.997 g/mol
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Compounds with the formula C15H14N2O3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 100 of 549 compounds

Frequently asked questions

What is the molar mass of C15H14N2O3?

The molar mass of C15H14N2O3 is 270.29 g/mol, calculated from standard atomic weights for 15 carbon atoms, 14 hydrogen atoms, 2 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 270.1004 Da.

How many compounds have the formula C15H14N2O3?

CompoundList lists 549 compounds with the molecular formula C15H14N2O3, including 10,11-Dihydroxycarbamazepine, Benzoic (4-hydroxy-3-methoxybenzylidene)hydrazide, 5-(6-Methoxynaphthalen-2-yl)-5-methylimidazolidine-2,4-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H14N2O3?

C15H14N2O3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.