C17H14ClNO3
107 compounds have this formula on CompoundList.
- Molar mass
- 315.75g/mol
- Monoisotopic mass
- 315.0662Da
- Atoms
- 36
- Elements
- 5
- Rings plus double bonds
- 11
The formula C17H14ClNO3 describes a molecule made of 17 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1764.67%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 144.47%1.008 × 14 = 14.112 g/mol
- Cl Chlorine × 111.23%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 14.44%14.007 × 1 = 14.007 g/mol
- O Oxygen × 315.20%15.999 × 3 = 47.997 g/mol
Compounds with the formula C17H14ClNO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 101 to 107 of 107 compounds
Frequently asked questions
What is the molar mass of C17H14ClNO3?
The molar mass of C17H14ClNO3 is 315.75 g/mol, calculated from standard atomic weights for 17 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 315.0662 Da.
How many compounds have the formula C17H14ClNO3?
CompoundList lists 107 compounds with the molecular formula C17H14ClNO3, including 5-Chloro-9-oxo-N-(propan-2-yl)-9H-xanthene-2-carboxamide, 4-Quinolinecarboxylic acid, 2-(4-hydroxyphenyl)-, methyl ester, hydrochloride (1:1), Benzyl N-(6-chloro-3-oxo-2,3-dihydro-1H-inden-5-yl)carbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C17H14ClNO3?
C17H14ClNO3 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.