CompoundList
Molecular formula

C22H25N3O5

108 compounds have this formula on CompoundList.

Molar mass
411.46g/mol
Monoisotopic mass
411.1794Da
Atoms
55
Elements
4
Rings plus double bonds
12

The formula C22H25N3O5 describes a molecule made of 22 carbon atoms, 25 hydrogen atoms, 3 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2264.22%
    12.011 × 22 = 264.242 g/mol
  • H Hydrogen × 256.12%
    1.008 × 25 = 25.200 g/mol
  • N Nitrogen × 310.21%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 519.44%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C22H25N3O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 101 to 108 of 108 compounds

Frequently asked questions

What is the molar mass of C22H25N3O5?

The molar mass of C22H25N3O5 is 411.46 g/mol, calculated from standard atomic weights for 22 carbon atoms, 25 hydrogen atoms, 3 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 411.1794 Da.

How many compounds have the formula C22H25N3O5?

CompoundList lists 108 compounds with the molecular formula C22H25N3O5, including tert-Butyl 4-(4-benzoylpiperazin-1-yl)-2-nitrobenzoate, 3-(Dimethylamino)-2-[2-({[(9H-fluoren-9-yl)methoxy]carbonyl}amino)acetamido]propanoic acid, 2-[3-(Dimethylamino)-2-({[(9H-fluoren-9-yl)methoxy]carbonyl}amino)propanamido]acetic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C22H25N3O5?

C22H25N3O5 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.