C2HBrClF3
6 compounds have this formula on CompoundList.
- Molar mass
- 197.38g/mol
- Monoisotopic mass
- 196.8965Da
- Atoms
- 8
- Elements
- 5
- Rings plus double bonds
- 0
The formula C2HBrClF3 describes a molecule made of 2 carbon atoms, 1 hydrogen atom, 1 bromine atom, 1 chlorine atom and 3 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 212.17%12.011 × 2 = 24.022 g/mol
- H Hydrogen × 10.51%1.008 × 1 = 1.008 g/mol
- Br Bromine × 140.48%79.904 × 1 = 79.904 g/mol
- Cl Chlorine × 117.96%35.45 × 1 = 35.450 g/mol
- F Fluorine × 328.88%18.998 × 3 = 56.994 g/mol
Compounds with the formula C2HBrClF3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 6 of 6 compounds
Frequently asked questions
What is the molar mass of C2HBrClF3?
The molar mass of C2HBrClF3 is 197.38 g/mol, calculated from standard atomic weights for 2 carbon atoms, 1 hydrogen atom, 1 bromine atom, 1 chlorine atom and 3 fluorine atoms. The monoisotopic mass is 196.8965 Da.
How many compounds have the formula C2HBrClF3?
CompoundList lists 6 compounds with the molecular formula C2HBrClF3, including Halothane, (R)-Halothane, 1-Bromo-2-chloro-1,1,2-trifluoroethane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C2HBrClF3?
C2HBrClF3 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.