C37H41F3N2O11S
1 compound has this formula on CompoundList.
- Molar mass
- 778.79g/mol
- Monoisotopic mass
- 778.2383Da
- Atoms
- 95
- Elements
- 6
- Rings plus double bonds
- 17
The formula C37H41F3N2O11S describes a molecule made of 37 carbon atoms, 41 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms, 11 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3757.06%12.011 × 37 = 444.407 g/mol
- H Hydrogen × 415.31%1.008 × 41 = 41.328 g/mol
- F Fluorine × 37.32%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 23.60%14.007 × 2 = 28.014 g/mol
- O Oxygen × 1122.60%15.999 × 11 = 175.989 g/mol
- S Sulfur × 14.12%32.06 × 1 = 32.060 g/mol
Compounds with the formula C37H41F3N2O11S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C37H41F3N2O11S?
The molar mass of C37H41F3N2O11S is 778.79 g/mol, calculated from standard atomic weights for 37 carbon atoms, 41 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms, 11 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 778.2383 Da.
How many compounds have the formula C37H41F3N2O11S?
CompoundList lists 1 compound with the molecular formula C37H41F3N2O11S, including Tipranavir glucuronide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C37H41F3N2O11S?
C37H41F3N2O11S has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.