CompoundList
Molecular formula

C9H10ClFO

133 compounds have this formula on CompoundList.

Molar mass
188.63g/mol
Monoisotopic mass
188.0404Da
Atoms
22
Elements
5
Rings plus double bonds
4

The formula C9H10ClFO describes a molecule made of 9 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 1 fluorine atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 957.31%
    12.011 × 9 = 108.099 g/mol
  • H Hydrogen × 105.34%
    1.008 × 10 = 10.080 g/mol
  • Cl Chlorine × 118.79%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 110.07%
    18.998 × 1 = 18.998 g/mol
  • O Oxygen × 18.48%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C9H10ClFO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 100 of 133 compounds

Frequently asked questions

What is the molar mass of C9H10ClFO?

The molar mass of C9H10ClFO is 188.63 g/mol, calculated from standard atomic weights for 9 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 1 fluorine atom and 1 oxygen atom. The monoisotopic mass is 188.0404 Da.

How many compounds have the formula C9H10ClFO?

CompoundList lists 133 compounds with the molecular formula C9H10ClFO, including 1-(3-Chloropropoxy)-4-fluorobenzene, 1-(3-Chloropropoxy)-2-fluorobenzene, 1-(2-Chloro-6-fluorophenyl)propan-1-ol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C9H10ClFO?

C9H10ClFO has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.