CompoundList

Dilution calculator

Solve the dilution equation C1V1 = C2V2 for any one value: how much stock to take, how far to dilute, or what concentration you end up with. Mix units freely, and plan a serial dilution below.

Solve for

The greyed field is the one being calculated. Units can differ between fields, the calculator converts them.

Volume of stock to take

25mL

Dilution factor 10 (1 in 10).

How to make it

Take 25 mL of the stock and add 225 mL of solvent to reach 250 mL in total.

C1 × V1 = C2 × V2 → 1 M × 25 mL = 0.1 M × 250 mL

For accurate work add the stock to a volumetric flask and fill to the mark, rather than adding a measured volume of solvent, because volumes are not always additive.

How the calculation works

Diluting a solution adds solvent but no solute, so the amount of solute is the same before and after. Amount equals concentration times volume, which gives the dilution equation.

C1 × V1 = C2 × V2
Amount of solute in the stock = amount of solute in the diluted solution
C1
concentration of the stock solution
V1
volume of stock you take
C2
concentration of the diluted solution
V2
final total volume after dilution

Rearrange for the value you need, for example V1 = C2 × V2 ÷ C1. The volume of solvent to add is V2 − V1, and the dilution factor is C1 ÷ C2 = V2 ÷ V1. Any concentration unit works as long as C1 and C2 use the same kind of unit, and any volume unit works as long as you convert V1 and V2 consistently. The calculator does the conversions for you.

The equation is for diluting with pure solvent. To blend two solutions of different strength use C1V1 + C2V2 = Cf × (V1 + V2), and remember that some liquids, such as ethanol and water, shrink slightly when mixed, so fill to the mark rather than adding volumes.

Worked example

The same steps the calculator follows, done by hand

You need 250 mL of 0.1 M hydrochloric acid and you have a 1 M stock.

  1. 1
    Write down what you know: C1 = 1 M, C2 = 0.1 M, V2 = 250 mL. V1 is unknown.
  2. 2
    Rearrange: V1 = C2 × V2 ÷ C1 = 0.1 × 250 ÷ 1 = 25 mL.
  3. 3
    Solvent to add: 250 − 25 = 225 mL. The dilution factor is 1 ÷ 0.1 = 10, a 1 in 10 dilution.
  4. 4
    Starting from concentrated acid at about 12.1 M instead, V1 = 0.1 × 250 ÷ 12.1 = 2.07 mL. Always add acid to water, never water to acid, and work in a fume hood with eye protection.

Serial dilution planner

Repeat the same dilution step to cover a wide range, such as a calibration curve

×

For each step move 100 µL from the previous tube into 900 µL of solvent and mix well.

TubeConcentrationTotal dilutionMade from
Stock1 mM1Starting solution
10.1 mM1 in 10100 µL of stock + 900 µL solvent
20.01 mM1 in 100100 µL of tube 1 + 900 µL solvent
30.001 mM1 in 1,000100 µL of tube 2 + 900 µL solvent
40.0001 mM1 in 10,000100 µL of tube 3 + 900 µL solvent
51 × 10⁻⁵ mM1 in 100,000100 µL of tube 4 + 900 µL solvent
61 × 10⁻⁶ mM1 in 1,000,000100 µL of tube 5 + 900 µL solvent

Frequently asked questions

What does a 1 in 10 dilution mean?
One part of stock in ten parts of final solution, for example 1 mL of stock made up to 10 mL. It is the same as a dilution factor of 10, or one part stock plus nine parts solvent.
Is a 1:10 dilution the same as 1 in 10?
Not always. Some people use 1:10 to mean one part stock in ten parts total, others mean one part stock plus ten parts solvent, which is 1 in 11. Write the dilution as stock volume and final volume to avoid confusion.
Can I use percentages or mg/mL in C1V1 = C2V2?
Yes. The equation works with any concentration unit as long as C1 and C2 use the same one, such as both in percent or both in mg/mL. To go between molar and mass units you need the molar mass, which the unit converter can handle.
How do I dilute a 10× buffer to 1×?
Choose the fold unit for both concentrations. For 500 mL of 1× buffer from 10× stock, V1 = 1 × 500 ÷ 10 = 50 mL of stock plus 450 mL of water.
Why is my diluted volume slightly off when I mix ethanol and water?
Ethanol and water contract when mixed, so 50 mL plus 50 mL gives a little less than 100 mL. For accurate dilutions add the stock to a volumetric flask and fill to the mark with solvent.